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V-q graph for capacitor |
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Answer» 1 is the most accurate answer but graph will never tip down at the end , slope TENDS to BECOME zero at infinity.Explanation:Let us assume a case of some resistance in the wires during CONNECTION of the capacitor plates to the battery.Emf of the battery is ECapacitance of the capacitor is Cresistance of the wires is RNow , using kirchoff loop RULE E - iR - q/c =0since I=dq/dtThe above equation is a first order variable separable .After solving the equation , and placing the boundary conditions ( at t=0 , charge is zero)the solution isq=CE( 1 - e^(-t/RC))we also know that at any instant , potential difference across a capacitor is q/cV=q/c= E(1 - e^(-t/RC))since q/v is constant q=CV the plot is a straight line |
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