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(v) Find the value of k, if the roots of the quadratic equation 3x2 – IT + 48=0are real and equal. |
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Answer» We have to find the VALUE of k , if the roots of the quadratic equation 3x² - KX + 48 = 0 are real and equal. solution : The roots of a quadratic equation ax² + bx + c = 0 are real and equal only when b² = 4ac for 3x² - kx + 48 = 0 a = 3 , b = -k and c = 48 so, (-k)² = 4 × 3 × 48 ⇒k² = 4 × 3 × 3 × 16 = 4 × 9 × 16 ⇒k² = (2 × 3 × 4)² ⇒k = ± 24 Therefore the value of k is ±24 also read similar questions : Find the values of 'k' for which the quadratic equation 2x + 3x2 + k = 0 has real roots Find the value of K if the quadratic equation 3x2-k√3x+4=0 has equal roots |
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