v) 403 vi) vii)V1) :58-888viii) i30 ii5060i 50 – InterviewSolution

1.	v) 403 vi) vii)V1) :58-888viii) i30 ii5060i 50
Answer» (v) i^403=i^400i^3=1i^3=i^2i=-i(vi)1/(i^58)=1/(i^56i^2)=1/(1(-1))=-1(vii)i^(-888)=i^888=1(viii)i^30+i^40+i^50+i^60=i^28i^2+1+i^48i^2+1 = 1i^2+1+1*i^2+1=-1+1-1+1=0

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