Using x = π/3, y = π/6 verify: cos(x+y) = cosx + cosy.

1.	Using x = π/3, y = π/6 verify: cos(x+y) = cosx + cosy.
Answer» Given \(x = \frac \pi3\), \(y = \frac \pi 6\) L.H.S. = \(cos(x + y) = cos(\frac\pi3 + \frac\pi 6) = cos(\frac \pi 2) = 0\) R.H.S. = \(cos x + cos y = cos(\frac \pi3) + cos(\frac\pi 6) = \frac 12 +\frac{\sqrt 3}2 \ne 0\) Hence, \(L.H.S. \ne R.H.S.\) Hence, at \(x = \frac\pi3 \) & \(y = \frac \pi 6, cos (x + y) \ne cos x + cos y\).

Answer»

Given \(x = \frac \pi3\), \(y = \frac \pi 6\)

L.H.S. = \(cos(x + y) = cos(\frac\pi3 + \frac\pi 6) = cos(\frac \pi 2) = 0\)

R.H.S. = \(cos x + cos y = cos(\frac \pi3) + cos(\frac\pi 6) = \frac 12 +\frac{\sqrt 3}2 \ne 0\)

Hence, \(L.H.S. \ne R.H.S.\)

Hence, at \(x = \frac\pi3 \) & \(y = \frac \pi 6, cos (x + y) \ne cos x + cos y\).

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Using x = π/3, y = π/6 verify: cos(x+y) = cosx + cosy.

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