Using the laws of exponents find the value of (3x*9x+1)÷(3x-1*9x-1)�

1.	Using the laws of exponents find the value of (3x9x+1)÷(3x-19x-1)
Answer» ${\red{\bf{\underline{\underline{\bigstar \:\: Question : \:\:\bigstar}}}}}\\$ $(3x9x+1)÷(3x-19x-1)$ ${\orange{\bf{\underline{\underline{\bigstar \:\: Solution : \:\:\bigstar}}}}}\\$ $(3x9x+1)÷(3x-19x-1)$ $⇒ ({27x}^{2}+3x)÷({27x}^{2}-9x-3x+1)$ $⇒ ({27x}^{2}+3x)÷({27x}^{2}-12x+1)$ $⇒ \frac{({27x}^{2}+3x)}{({27x}^{2}-12x+1)}$ ${\green{\bf{\underline{\underline{\bigstar \:\: Answer : \frac{({27x}^{2}+3x)}{({27x}^{2}-12x+1)} \:\:\bigstar}}}}}\\$