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Using the given figure, prove that the triangles are congruent. Can you conclude that AC is parallel to DE. |
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Answer» In ∆ABC and ∆EBD, AB = EB BC = BD ∠ABC = ∠EBD [∵ Vertically opposite angles] By SAS congruency criteria. ∆ABC ≅ ∆EBD. We know that corresponding parts of congruent triangles are congruent. ∴ ∠BCA ≅ ∠BDE and ∠BAC ≅ ∠BED ∠BCA ≅ ∠BDE means that alternate interior angles are equal if CD is the transversal to lines AC and DE. Similarly, if AE is the transversal to AC and DE, we have ∠BAC ≅ ∠BED Again interior opposite angles are equal. We can conclude that AC is parallel to DE. |
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