1.

Using the given figure, prove that the triangles are congruent. Can you conclude that AC is parallel to DE.

Answer»

In ∆ABC and ∆EBD,

AB = EB 

BC = BD 

∠ABC = ∠EBD [∵ Vertically opposite angles] 

By SAS congruency criteria. ∆ABC ≅ ∆EBD. 

We know that corresponding parts of congruent triangles are congruent. 

∴ ∠BCA ≅ ∠BDE and 

∠BAC ≅ ∠BED 

∠BCA ≅ ∠BDE means that alternate interior angles are equal if CD is the transversal to lines AC and DE. 

Similarly, if AE is the transversal to AC and DE, we have ∠BAC ≅ ∠BED 

Again interior opposite angles are equal. 

We can conclude that AC is parallel to DE.



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