Using the data (all value are in kilocalorie per mole at 25∘C ) given below, the bond energy of C−C and bond C−H bond is m kcal and n kcal, respectively. Calculate the value of m+nΔH∘combustion of ethane=−372.0ΔH∘Combustion of propane=−530.0ΔH∘forC(graphite)→C(g)=+172.0Bond energy of H - H bond=+104.0ΔH∘f of H2O(l)=−68.0ΔH∘f of CO2(g)=−94.0

Using the data (all value are in kilocalorie per mole at 25∘C ) give

1.	Using the data (all value are in kilocalorie per mole at 25∘C ) given below, the bond energy of C−C and bond C−H bond is m kcal and n kcal, respectively. Calculate the value of m+nΔH∘combustion of ethane=−372.0ΔH∘Combustion of propane=−530.0ΔH∘forC(graphite)→C(g)=+172.0Bond energy of H - H bond=+104.0ΔH∘f of H2O(l)=−68.0ΔH∘f of CO2(g)=−94.0
Answer» Using the data (all value are in kilocalorie per mole at $25^{\circ} C$ ) given below, the bond energy of $C - C$ and bond $C - H$ bond is $m k c a l$ and $n k c a l$ , respectively. Calculate the value of $m + n$ $Δ H_{combustion of ethane}^{\circ} = - 372.0 Δ H_{Combustion of propane}^{\circ} = - 530.0 Δ H^{\circ} f o r C_{(graphite)} \to C (g) = + 172.0 Bond energy of H - H bond = + 104.0 Δ H_{f}^{\circ} o f H_{2} O (l) = - 68.0 Δ H_{f}^{\circ} o f C O_{2} (g) = - 94.0$