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Using Raoult's law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions. (i) CHCl_(3)(l) and CH_(2)Cl_(2)(l) |
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Answer» Solution :(i) As both the components are VOLATILE, in the solution `p_(CHCl_(3))=x_(CHCl_(3))xxp_(CHCl_(3))^(@)"and"p_(CH_(2)Cl_(2))xxp_(CH_(2)Cl_(2))^(@)` `P_("total")orP_("SOLN")=x_(CHCl_(3))p_(CHCl_(3))^(@)+x_(CH_(2)Cl_(2))p_(CH_(2)Cl_(2))^(@)=x_(CHCl_(3))p_(CHCl_(3))^(@)+(1-x_(CHCl_(3)))p_(CH_(2)Cl_(2))^(@)``=(p_(CHCl_(3))^(@)-p_(CH_(2)Cl_(2))^(@))x_(CHCl_(3))+p_(CH_(2)Cl_(2))^(@)` |
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