Saved Bookmarks
| 1. |
Using Euclid's division algorithm find the HCF of the numbers 867 and 2515 |
|
Answer» By using EDLa=bq+rwhere a is > bso a =867 and b=255867=255×3+102here r≠0 so a=255 and b=102255=102×2+51here r≠0 so a=102 and b=51102=51×2+0here r=0so, HCf of (867,255) is =51 |
|