1.

Using euclid`s algorithm ,find tha hcf of 405 and 2520 , 504 and 1188

Answer»

(1)2520=405×6+90

405=90×4+45

90=45×2+0

so hcf = 45

(2)1188=504×2+180

504=180×2+144

180=144×1+36

144=36×4+0

hcf = 36

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