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Using euclid`s algorithm ,find tha hcf of 405 and 2520 , 504 and 1188 |
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Answer» (1)2520=405×6+90 405=90×4+45 90=45×2+0 so hcf = 45 (2)1188=504×2+180 504=180×2+144 180=144×1+36 144=36×4+0 hcf = 36 PLEASE MARK MY ANSWER AS BRAINLIST |
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