Saved Bookmarks
| 1. |
Using Euclid's algorith(i) 1240 and 1984 |
|
Answer» Make two columns of numbers. At the head of the columns write the two numbers whose HCF you seek: 1240.........1984 In the next step, under the smaller of the two numbers just repeat the number; under the larger number write (larger number - smaller number) so at the end of the first step you have 1240.........19841240.......... 744 Now do the same thing with the numbers you just wrote down: 1240.........19841240.......... 744. 496...........744 And so on: 1240.........19841240.......... 744. 496...........744. 496...........248 1240.........19841240.......... 744. 496...........744. 496...........248. 248...........248 When the two numbers are equal, stop. This is the HCF of the original two numbers |
|