1.

Using Euclid division algorithm, find the HCF of 4052 and 12576.

Answer»

12576>4052 by euclid division alogrinthm 12576=4052*3 +420

4052=420*9+272 420=272*1+148

272=148*1+124

148=124*1+24

124=24*5+4

24=4*6+0 as the process stops .

so our HCF is 4

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