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Usha swims in a90m long.She covers 180m in one mine minute by swimming from one end to the other and back along the same straight path . find the average and speed velocity of Usha |
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Answer» Distance = 180 m Time = 1 min = 60sec Average speed = TOTAL distance covered / total time TAKEN = 180m / 60 sec = 3m/s Displacement = 0m/s ( as usha COME back along the same path so, the intial and final position is same ) Average VELOCITY = displacement/ time = 0m / 60 s = 0m/s HOPE IT HELPS. |
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