______User gone die I'm in depression it's not a joke

1.	______User gone die I'm in depression it's not a joke
Answer» Explanation: Answer: Given :- Initial velocity of bus (U) = 0 m/s Acceleration of bus (A) = 2 m/s Time taken (T) = 4 m ➡ 240 second To find :- ❶ Speed required ❷ Distance travelled SoluTion For find speed, We will use newton first Equation \fbox {v \: = u + at} v = u + at Here, V = FINAL Velocity U = Initial velocity A = Acceleration T = Time \SF \: v \: = 0 + 2 \times 20v=0+2×20 \sf \: v \: = 0 + 40v=0+40 \sf \: \: v \: = 40 \: mpsv=40mps Now finding distance travelled by using newton third Equation \boxed { \sf \: s \: = UT + \dfrac{1}{2} \times a {t}^{2} } s=ut+ 2 1 ×at 2 Here, S = Distance travelled U = Initial velocity T = Time taken A = Acceleration \sf \: s \: = 0 \times 20 + \dfrac{1}{2} \times 2 \times {240}^{2}s=0×20+ 2 1 ×2×240 2 \sf \: s \: = 0 + \dfrac{1}{2} \times 240 \times 240s=0+ 2 1 ×240×240 \sf \: s \: = 57600 \: ms=57600m

Answer»

Explanation:

Answer:

Given :-

Initial velocity of bus (U) = 0 m/s

Acceleration of bus (A) = 2 m/s

Time taken (T) = 4 m ➡ 240 second

To find :-

❶ Speed required

❷ Distance travelled

SoluTion

For find speed,

We will use newton first Equation

\fbox {v \: = u + at}

v = u + at

Here,

V = FINAL Velocity

U = Initial velocity

A = Acceleration

T = Time

\SF \: v \: = 0 + 2 \times 20v=0+2×20

\sf \: v \: = 0 + 40v=0+40

\sf \: \: v \: = 40 \: mpsv=40mps

Now finding distance travelled by using newton third Equation

\boxed { \sf \: s \: = UT + \dfrac{1}{2} \times a {t}^{2} }

s=ut+

×at

Here,

S = Distance travelled

U = Initial velocity

T = Time taken

A = Acceleration

\sf \: s \: = 0 \times 20 + \dfrac{1}{2} \times 2 \times {240}^{2}s=0×20+

×2×240

\sf \: s \: = 0 + \dfrac{1}{2} \times 240 \times 240s=0+

×240×240

\sf \: s \: = 57600 \: ms=57600m

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