1.

Use the assumptions of the previous question. An object weighed by a spring balance at the equator gives the same reading as a reading taken at a depth d below the earth.s surface at a pole (d

Answer»

`(omega^(2)R^(2))/g`
`(omega^(2)R^(2))/(2g)`
`(2OMEGA^(2)R_(0)^(2))/g`
`SQRT(Rg)/omega`

ANSWER :A


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