Urgentif 1.0 Kcal of heat is added to 1.2 L of O2 in a cylinder of con

1.	Urgentif 1.0 Kcal of heat is added to 1.2 L of O2 in a cylinder of constant pressure of 1 atm ,the volume increases to 1.5 L. calculate delta U delta H of the process.
Answer» $\Delta U=992.737cal$ $\Delta H=1000cal$ Answer : and Solution : Given, Heat = 1 Kcal = 1000 CAL (1 Kcal = 1000 cal) Initial volume = 1.2 L Final volume = 1.5 L Pressure = 1 atm Formula used : $\Delta U=q-w\\\Delta U=q-P\Delta V\\\Delta U=q-P(V_{final}-V_{initial})$ Now PUT all the given VALUES in this formula, we get $\Delta U=1000cal-[1atm\times (1.5L-1.2L)]\times 24.21=992.737cal$ $(1Latm=24.21cal)$ $\Delta H$ Now we have to CALCULATE the . At constant pressure, $\Delta H=q_p$ So, $\Delta H=q_p=1000cal$ $\Delta U=992.737cal$ $\Delta H=1000cal$ THEREFORE, and