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Upon heating`KClO_(3)` in presence of catalytic amount of `MnO_(2)`, a gas `W` is formed. Excess amount of `W` reacts with white phosphorus to given `X`. The reaction of `X` with pure `HNO_(3)` gives `Y` and `Z`. Y and Z are, respectivelyA. `N_(2)O_(4) " and " HPO_(3)`B. `N_(2)O_(4) " and " H_(3)PO_(3)`C. `N_(2)O_(3) " and " H_(3)PO_(4)`D. `N_(2)O_(5) " and " HPO_(3)` |
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Answer» Correct Answer - D It is the correct answer. `2KClO_(3) overset((MnO_(2))) underset("heat")to 2KCl+underset((W))(3O_(2))` `5O_(2)+P_(4) to underset((X))(P_(4)O_(10))` `P_(4)O_(10) + 4HNO_(3) to underset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))` |
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