UP!If the mean of the following distribution is 6, then find the value

1.	UP!If the mean of the following distribution is 6, then find the value of p.* 12 14 16 10 (p+5y 3 2 3 1À5964
Answer» 27.5 sigma xy=6+8+18+10+2p+10=2p+52sigma y = 3+2+3+1+2=11mean=sigma xy/sigma y6=2p+52/112p+52=6×112p+52=662p=66-522p=14p=7Abs)The value of p is 7. sigma xy=6+8+18+10+2p+10=2p+52sigma y = 3+2+3+1+2=11mean=sigma xy/sigma y6=2p+52/112p+52=6×112p+52=662p=66-522p=14p=7Abs)The value of p is 7.

UP!If the mean of the following distribution is 6, then find the value of p.* 12 14 16 10 (p+5y 3 2 3 1À5964

Answer»

27.5

sigma xy=6+8+18+10+2p+10=2p+52sigma y = 3+2+3+1+2=11mean=sigma xy/sigma y6=2p+52/112p+52=6×112p+52=662p=66-522p=14p=7Abs)The value of p is 7.