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-UO and -2ates the join of (-4, 3) und (6, 3) then the value of v2. y = 43.y-34. y=2B(5,k) and C(6,7) are collinear, then the value of kis-6 and 1The point (2. divides the join31. y2.2.3), B(5, k) and C(6, 7) are con |
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Answer» fast plz Answer:3).y=3Explanation: Let the required ratio be k:1Then, 2 = 6k-4×1/k+1 ⇒ k = 3/2.Therefore the required ratio is 3/2: 1 i.e. 3:2 Also, y = 3×3+2×3/3+2 = 3. tq tq |
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