Saved Bookmarks
| 1. |
Unlessstated otherwise, use π =Find the area of the shaded region in Fig. 5.19, if PQ= 24 cm, PR = 7 cm and O is the centre ofthe circle.1. |
|
Answer» Given thatPQ=24cm,PR=7cm,QR=? From Pythagoras theoremQR=√PQ^2+PR^2 =√24^2+7^2 =√576+49 =√625 =25cmhere redius of the circle,r=25/2cmthen area of shaded region=area of semicircle-area of ∆PQR=1/2πr^2-1/2PR×PQ=1/2{πr^2-PR×PQ}=1/2{22/7×25/2×25/2-7×24}=1/2{11×625/14-168}=6875/28-168/2=6875-2352/28=4523/28 cm^2 |
|