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| 1. |
`underset("n-digits")((666 . . . .6)^(2))+underset("n-digits")((888 . . . .8))` is equal toA. `(4)/(9)(10^(n)-1)`B. `(4)/(9)(10^(2n)-1)`C. `(4)/(9)(10^(n)-1)^(2)`D. none of these |
| Answer» Correct Answer - B | |