1.

`underset((A))(PhCOOH)underset(underset((ii)Ag_(2)O //Pt//MeOH)((ii)CH_(2)N_(2)))overset((i)SOCI_(2))rarr (B)` Product `(B)` is :A. `PhCONH_2`B. `PhCH_2 COOH`C. `PhCH_2 COOMe`D. `PhCONHMe`

Answer» Correct Answer - C
Arndt-Eistert reaction . The product `PhCH=C=O` (ketone) reacts with `MeOH` to give ester `(PhCH_2 COOMe)` (step up by one `C` atom).


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