1.

Under the same reaction condition the initial concentration of 1.386 mol dm^(-3) of a substance becomes half in 40 seconds and 20 seconds through first order and zero order kinetics. Ratio ((K_(1))/(K_(0))) of the ratio constants for first order (K_(1)) and zero order (K_(0)) of the reaction is :

Answer»

`0.5mol^(-1)DM^(-3)`
`1.0mol^(-1)dm^(-3)`
`1.5mol^(-1)dm^(-3)`
`2.0mol^(-1)dm^(-3)`

SOLUTION :`K_(1)=(0.693)/(t_(1//2))=(0.693)/(40)`
`K_(0)=(a)/(2t_(1//2))=(1.386)/(2xx20)`
`:.(K_(1))/(K_(0))=(0.693)/(1.386)=0.5`


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