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Under the influence of a force, an object of mass 4 kg accelerates from 3 m/s to 6 m/s in 8s. How much work was done on the object during this time? |
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Answer» 27J `W=DeltaK=(1)/(2)m(V^(2)-v_(0)^(2))=(1)/(4)(4kg)[(6m//s)^(2)-(3m//s)^(2)]=54J`. |
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