Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x=t33, where x is in meter and t in second. The work done by the force in the first two seconds is

Under the action of a force, a 2 kg body moves such that its position

1.	Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x=t33, where x is in meter and t in second. The work done by the force in the first two seconds is
Answer» Under the action of a force, a $2 kg$ body moves such that its position $x$ as a function of time t is given by $x = \frac{t^{3}}{3}$ , where $x$ is in meter and $t$ in second. The work done by the force in the first two seconds is

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Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x=t33, where x is in meter and t in second. The work done by the force in the first two seconds is

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