1.

under identical conditions of temperature and pressure 4l of gaseous mixture i.e. H2 and CH4 diffuses through a hole in 5min. whereas 4L of a gas X of molar mass 36 takes 10 min to diffuse through a same hole. mole ratio of H2 :CH4 in the mixture will be

Answer»

Answer:

1:1.

Explanation:

From the chapter of the STATES of matter we know that the molar mass is INVERSELY proportional to the radius of the gasses. So, we GET that the radius of GAS 1 to the radius of gas 2 will be √(molar mass of gas 2/molar mass of the gas 1).

While we know that the radius can also be written as time of gas 1 / time of gas 2 to diffuse. So, 4v/t1*t2/4v = √(36/(H2+CH4)) which will be                     10/5 = 6/√(H2+CH4). Which will be (H2+CH4)=9.

Now, if the moalr ratios are taken x and y for CH4 and H2 respectively. So, 16*x + 2*y/x+y = 9 or 7x=7y or x/y will be 1:1.  


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