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Under a constant pressure, the rate of flow of liquid through capillary is V. if the length of capillary is doubled and the diameter of the bore is halved, the rate of flow would be …… |
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Answer» `(V)/(4)` RATE of FLOW `V=(piPr^(4))/(8etal)` DIAMETER `d.=(d)/(2)thereforer.=(R)/(2)` and `l=2l` `V.=(pip(r.)^(4))/(8etal)` `thereforeV.=(pip((r)/(2))^(4))/(8eta(2l))` `thereforeV.(pip((r^(4))/(16)))/(2(8etal))` `thereforeV.=(pipr^(4))/(32(8etal))` `thereforeV.=(V)/(32)` |
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