um of five consecutive even numbers is 250. Sum of theargest number an

1.	um of five consecutive even numbers is 250. Sum of theargest number and square of the smallest number will beUttranchal Gr. Bank Ci. 20111
Answer» Let terms are n-4, n-2, n, n+2 , n+4 Sum=n-4+n-2+n+n+2+n+4250=5nn=250/5=50 Sum of largest number and square of smallest number=n+4+(n-4)²=50+4+(50-4)²=54+46²=54+2116=2170

um of five consecutive even numbers is 250. Sum of theargest number and square of the smallest number will beUttranchal Gr. Bank Ci. 20111

Answer»

Let terms are n-4, n-2, n, n+2 , n+4

Sum=n-4+n-2+n+n+2+n+4250=5nn=250/5=50

Sum of largest number and square of smallest number=n+4+(n-4)²=50+4+(50-4)²=54+46²=54+2116=2170