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uest(a) Find the greatest number that divides 121, 183 and305 leaving 1, 3 and 5 as remainders respectively [5 |
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Answer» Just subtract the remainder from the dividend:121- 1 = 120183 -3 = 180305 -5 = 300 The required number is the HCF of 120, 180 and 300...which is 60 hence the required number is 60 Thanks |
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