1.

UAUL,(ii) The sum of the 4th and 8th term of an A.P. is 54 and their product is 665. Find the sum of the first 30 termof the A.P. (The terms of the AP are in ascending order)​

Answer»

Answer:

1920

Step-by-step EXPLANATION:

A4+A8=54

a+3d+a+7d=54

2A+10d=54

a+5d=27

a=27-5d ____eq.1

A4×A8=665

(a+3d)(a+7d) = 665

(27-5d+3d)(27-5d+7d)=665

(27-2d)(27+2d)=665

729+54d-54d-4d^2=665

-4d^2=665-729

-4d^2=-64

d^2=16

d=4

PUT the VALUE of d in eq.1

a=27-5×4

a=26-20

a=6

a=6,d=4,n=30

Sn=n/2[2a+(n-1)d]

S30=30/2[2×6+(30-1)×4]

S30=30/2[12+116]

S30=30/2×128

S30=30×64

S30=1920



Discussion

No Comment Found

Related InterviewSolutions