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Type II.10 (0) How many numbers of four digits can be formed with the di1, 2, 4, 5, 7 no digit being repeated ?senn ke formed with the digite

Answer»

So the total number is9*9*8*7=4536, beginning at1023, 1024, 1025, 1026, etc., and going up to9876. For each of these there is a negative counterpart (-1023, -1024, etc.), for a total of 2*4536=9072possibilities. There are4537 fourdigit-numbers with no digit repeated.



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