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Two years ago, Salim was thrice as old as his daughter and six years later, he will be four year older than twice her age. How old are they now? |
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Answer» Let Salim and his daughter’s age be x and y years respectively. Now, by first condition Two years ago, Salim was thrice as old as his daughter. i.e., x - = 3(y - 2) so, x - 3y = - 4 …(i) and by second condition, six years later. Salim will be four years older than twice her age. (x + 6) = 2(y + 6) + 4 x + 6 = 2y + 16 x – 2y = 10 …(ii) On subtracting Eq. (i) from Eq. (ii), we get x – 2y = 10 - (x–3y =- 4) We get, y = 14 Put the value of y in Eq. (ii), we get x - 2(14) = 10 so, x = 38 Hence, Salim and his daughter’s age are 38 year and 14 year, respectively. |
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