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Two wires of equal length, one of copper and the other of manganin have the same resistance. Which wire is thicker ? |
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Answer» Solution :`R_("copper")= rho_(C) (1_(c))/(A_(c))` `R_(m)= rho_(m)(l_(m))/(A_(m))` Now `"" R_(c) = R_(m) ` ( GIVEN ) `l_(c)=l_(m) ` (given ) `:. (rho_(m))/(A_(c))=(rho_(m))/(A_(m))` or `"" (rho_(c))/(rho_(m))=(A_(c))/(A_(m))` Since `"" rho_(m) lt rho_(c)` `:. "" A_(m) lt A_(c)` Copper wire will be thicker . |
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