1.

Two wires are made of the same material and have the same volume. The first wire has cross sectional area A and the second wire has cross sectional area 3A. If the length of the first wire is increased by Deltal on applying a force F, how much force needed to stretch the second wire by the same amount ?

Answer»

F
9F
4F
6F

Solution :Young.s MODULUS `y=F/(A DELTAL)` but `V=Al rArr l=V/A`
`THEREFORE y=(FV)/(A^2Deltal)`
`therefore F=(yA^2 Al)/V`, y , `Deltal` and V CONSTANT
`therefore F prop A^2`
`therefore F_2/F_1=(A_2/A_1)^2 = ((3A)/A)^2=9`
`therefore F_2=9F "" [ because F_1=F]`


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