Saved Bookmarks
| 1. |
Two wires `A` and `B` have equal lengths and are made of the same material , but diameter of wire `A` is twice that of wire `B`. Then, for a given load,A. The extension of `B` will be four times that of `A`B. the extension of `A` and `B` will be equalC. the strain in `B` is four times that in `A`D. the strains in `A` and `B` will be equal |
|
Answer» Correct Answer - A::C Area of cross section `A=(pid^(2))/4` where `d` is the diameter of the wire. Therefore `l=(4FL)/(pid^(2)Y)` since `F, L` and `Y` are the same for wires `A` and `B` `:. Lprop1/(d^(2))` i.e., the extension is inversely proportional to the square of the diameter. Hence choice a is correct.The strain is `l/L=(4F)/(pid^(2)Y)` Thus strain `prop1/(d^(2))` i.e., the extension is inversely proportional material to the square of the diameter. Hence choice a is correct. The strain is `l/L=(4F)/(pid^(2)Y)` Thus, strain`prop1/(d^(2))` Hence the correct choice are a and c. |
|