Two waves with wavelength lamda have phase difference of 60° at the point of superposition. Find path difference between them.

Two waves with wavelength lamda have phase difference of 60° at the p

1.	Two waves with wavelength lamda have phase difference of 60° at the point of superposition. Find path difference between them.
Answer» `lamda/6` `lamda/2` `2lamda` `lamda/4` SOLUTION :We have `Delta PHI = (2PI)/(lamda) (Delta x)` `THEREFORE (PI )/(3) = (2pi )/( lamda ) (Delta x)` `therefore Delta x = (lamda )/(6)`