Two voltages are = 100 sin (ω + 15°) and = 60 cosω, then

1.	Two voltages are = 100 sin (ω + 15°) and = 60 cosω, then
Answer» v1 = 100 sin (ωt + 15°) and v2 = 60 cos ωt = 60 sin (ωt + 90°). Hence, v2 is leading v1 by (90 - 15) = 75°.

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