Two vessels have different base area. They are filled with water to the same height. If theamount of water in one is 4 times that in theother, then the ratio of pressure on theirbottom will be(A) 16:1(B) 8:1(C) 4:1(D) 1:1

Two vessels have different base area. They are filled with water to

1.	Two vessels have different base area. They are filled with water to the same height. If theamount of water in one is 4 times that in theother, then the ratio of pressure on theirbottom will be(A) 16:1(B) 8:1(C) 4:1(D) 1:1
Answer» TION:Given that,P( Aˉ )P(A) = 115 We know that,P( Aˉ )=1−P(A)Now,1−P(A)P(A) = 115 ⇒11P(A)=5−5P(A)⇒16P(A)=5⇒P(A)= 165 and P( Aˉ )=1−P(A)=1− 165 = 1611

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Two vessels have different base area. They are filled with water to the same height. If theamount of water in one is 4 times that in theother, then the ratio of pressure on theirbottom will be(A) 16:1(B) 8:1(C) 4:1(D) 1:1​

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Two vessels have different base area. They are filled with water to the same height. If theamount of water in one is 4 times that in theother, then the ratio of pressure on theirbottom will be(A) 16:1(B) 8:1(C) 4:1(D) 1:1