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Two uniform solid cylinders A and B each of mass 1 kg are connected by a spring of constant `200Nm^(-1)` at their axles and are placed on a fixed wedge as shown in fig.There is no friction between cylinders and wedge. The angle made by the line AB with the horizontal, in equilibirum is A. `0^(@)`B. `15^(@)`C. `30^(@)`D. None of these |
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Answer» In equilibrium, there will not be any friction between the cylinder and the wedge. If `theta` be the required angle Cylinder `A : mg sin60^(@)=kx cos(60^(@)-theta)(-mg cos30^(@))` Cylinder `B : mg sin30^(@)=kx cos(30^(@)+theta)=kx sin(60^(@)-theta)` `:. cot30^(@)=cot(60^(@)-theta)rArrtheta=30^(@)`. |
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