Two triangles have an equal area of 24 cm2 and stand on the same base of 6 cm. If the distance PQ (on base) between their altitudes is equal to thrice the length of one of the altitude. Then the area of the quadrilateral formed by the altitudes and the base PQ is equal to:

Two triangles have an equal area of 24 cm2 and stand on the same base

1.	Two triangles have an equal area of 24 cm2 and stand on the same base of 6 cm. If the distance PQ (on base) between their altitudes is equal to thrice the length of one of the altitude. Then the area of the quadrilateral formed by the altitudes and the base PQ is equal to:
Answer» Two triangles have an equal area of $24 c m^{2}$ and stand on the same base of 6 cm. If the distance PQ (on base) between their altitudes is equal to thrice the length of one of the altitude. Then the area of the quadrilateral formed by the altitudes and the base PQ is equal to: