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Two trees A and B are same side of the river. From a point C in the river the distance trees A and B are 250m and 300 m respectively. If the angle C is 45°. Find the distancebetween the trees. (use root2 = 1.44) |
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Answer» InΔABC∠C = 45AC = 250 mBC = 300m by applying the cosine rulea²= b² + c² - 2bc cos Aso,AB² = AC² + BC² - 2 AC BC cos C= 250² + 300² - 2 x 250 x 300 x cos 45AB²= 46433.98taking under rootAB = 215.5 m |
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