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Two trains are moving in the opposite directions at speeds of 43 km/h and 51 km/h respec- tively. The time taken by the slower train to cross a man sit- ting in the faster train is 9 sec- onds. What is the length (in metre) of the slower train? |
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Answer» Explanation: VELOCITY of first TRAIN- 43km /h Velocity of second train = 51km/h According to the QUESTION, When the TWO heads of each train MEETS at a common point the total speed of slow train is equal to 43+51km/h=94mk/h=26.11m/s therefore distance of slow train=speed ×time =26.11×9 =234.99metres |
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