Two toroidal solenoids are wound around the same pipe so that the magnetic field of one passes through the turns of the other. Solenoid 1 has 700 turns and solenoid 2 has 400 turns. When the current in solenoid 1 is `6.52 A`, the average flux through each turn of solenoid 2 is `0.0320 Wb`. (a) What is the mutual inductance of the pair of solenoids? (b) When the current in solenoid 2 is `2.54 A`, what is the average flux through each solenoid 1?

Two toroidal solenoids are wound around the same pipe so that the magn

1.	Two toroidal solenoids are wound around the same pipe so that the magnetic field of one passes through the turns of the other. Solenoid 1 has 700 turns and solenoid 2 has 400 turns. When the current in solenoid 1 is `6.52 A`, the average flux through each turn of solenoid 2 is `0.0320 Wb`. (a) What is the mutual inductance of the pair of solenoids? (b) When the current in solenoid 2 is `2.54 A`, what is the average flux through each solenoid 1?
Answer» Correct Answer - A::B::C a. `M=(N_2phi_2)/i_2=((400)(0.032))/6.52=1.96H` b. `M=(N_1phi_1)/i_2` `phi_2=(Mi_2)/N_1=((1.96)(2.54))/700` `=7.12xx10^-3Wb`

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