Two-thirds of a number increased by 19 gives the result as 29 .find th

1.	Two-thirds of a number increased by 19 gives the result as 29 .find the number
Answer» $\huge {\red {\mathfrak{Question:-}}}$ Two-thirds of a number INCREASED by 19 gives the RESULT as 29. FND the number. $\huge {\pink {\mathfrak{Solution:-}}}$ Let the required number be x. Atq, $\implies( x \times \dfrac{2}{3}) + 19 = 29 \\ \\ \implies \dfrac{2x}{3} + 19 = 29 \\ \\ \implies \dfrac{2x}{3} = 29 - 19 \\ \\ \implies \dfrac{2x}{3} = 10 \\ \\ \implies 2x = 3 \times 10 \\ \\ \implies x = \dfrac{3 \times 10}{2} \\ \\ \implies x = 3\times 5 \\ \\ \implies x = 15$ $\green {\therefore{\tt {The\:required\:number\: is\:15.}}}$ $\rule {207}{1}$ $\underline{\bold {Verification:}}$ $\implies (15 \times \dfrac{2}{3}) + 19 = 29 \\ \\ \implies (5 \times 2) + 19 = 29 \\ \\ \implies 10 + 19 = 29 \\ \\ \implies 29 = 29$ $\rule {207}{2}$

Two-thirds of a number increased by 19 gives the result as 29 .find the number

Answer»

$\huge {\red {\mathfrak{Question:-}}}$

Two-thirds of a number INCREASED by 19 gives the RESULT as 29. FND the number.

$\huge {\pink {\mathfrak{Solution:-}}}$

Let the required number be x.

Atq,

$\implies( x \times \dfrac{2}{3}) + 19 = 29 \\ \\ \implies \dfrac{2x}{3} + 19 = 29 \\ \\ \implies \dfrac{2x}{3} = 29 - 19 \\ \\ \implies \dfrac{2x}{3} = 10 \\ \\ \implies 2x = 3 \times 10 \\ \\ \implies x = \dfrac{3 \times 10}{2} \\ \\ \implies x = 3\times 5 \\ \\ \implies x = 15$