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Two terminals of a cell are marked as X (+6V) and Y(-6V). The cell is connected to a wire of resistance (2ohm). calculate the work done in carrying a charge of 2C fromi) X to Y along the wire Rii) Y to X through the cell |
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Answer» i) X to y - work DONE = v x q so WORKDONE in moving 2c from x to y = 6 x 2 = 12 ii) y to x - its inside the cell , so the current is flowing from -6 to +6 potential difference = -6-(+6) = -12 workdone = v x q = -12 x 2 = -24 this maybe correct , although i aint sure!! if there's any correction please comment!! i will rectify!! hope this HELPS , drop in a thanks , mark as brainliest!! |
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