two taps fill the cistern 10 and 8 hours respectively a third tap can

1.	two taps fill the cistern 10 and 8 hours respectively a third tap can empty it in 15 hours how long will it take to fill the empty cistern if all of them are opend together
Answer» rong>ANSWER: *Volume filled by* *first* *tap* in 1 *HOUR* = 1/10 *Volume* *filled* by *SECOND* *tap* in 1 *hour* = 1/8 *Volume* *emptied* by *third* *tap* in 1 *hour* = 1/15 =>*Net* *volume* *filled* by *three* *taps* in 1 *hour* = (1/10)+(1/8)-(1/15) = 12+15-8/120 = 19/120 *Therefore, Time* *required* by *all* *three* *taps* to *fill* *FULL* *cistern* = 120/19 hours. HOPE IT HELPS YOU. *PLEASE* *MARK* AS *BRAINLIEST*...

two taps fill the cistern 10 and 8 hours respectively a third tap can empty it in 15 hours how long will it take to fill the empty cistern if all of them are opend together

Answer»

Volume filled by first tap in 1 HOUR = 1/10

Volume filled by SECOND tap in 1 hour = 1/8

Volume emptied by third tap in 1 hour = 1/15

=>Net volume filled by three taps in 1 hour

= (1/10)+(1/8)-(1/15)

= 12+15-8/120

= 19/120

Therefore,

Time required by all three taps to fill FULL cistern

= 120/19 hours.

HOPE IT HELPS YOU.

PLEASE MARK AS BRAINLIEST...