Two stones of masses 50g and 250g are dropped from a height of 100m si

1.	Two stones of masses 50g and 250g are dropped from a height of 100m simultaneously. What will be the ratio of time taken by them to touch the ground? (Take g=10 m per sec square)
Answer» Explanation: If AIR RESISTANCE is proportional to mass of the body, then acceleration due to it will be independent of mass and hence the two bodies will reach ground simultaneously. a= m mg−f AIA = m mg−mα =g−α This acceleration is independent of mass and hence same TIME will be required.

Two stones of masses 50g and 250g are dropped from a height of 100m simultaneously. What will be the ratio of time taken by them to touch the ground? (Take g=10 m per sec square)

Answer»

Explanation:

If AIR RESISTANCE is proportional to mass of the body, then acceleration due to it will be independent of mass and hence the two bodies will reach ground simultaneously.

mg−f

AIA

mg−mα

=g−α

This acceleration is independent of mass and hence same TIME will be required.

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Two stones of masses 50g and 250g are dropped from a height of 100m simultaneously. What will be the ratio of time taken by them to touch the ground? (Take g=10 m per sec square)

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