Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ration of u21 ; u22 ( Assume upward acceleration is –g and downward acceleration to be +g).

Two stones are thrown vertically upwards simultaneously with their ini

1.	Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ration of u21 ; u22 ( Assume upward acceleration is –g and downward acceleration to be +g).
Answer» Two stones are thrown vertically upwards simultaneously with their initial velocities $u_{1}$ and $u_{2}$ respectively. Prove that the heights reached by them would be in the ration of $u_{1}^{2}$ ; $u_{2}^{2}$ ( Assume upward acceleration is –g and downward acceleration to be +g).

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Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ration of u21 ; u22 ( Assume upward acceleration is –g and downward acceleration to be +g).

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