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Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speed `u_(1) = 30 m//sec` and `u_(2) = 50 m//sec`. Which of the curve represent correct variation (for the time interval in which both reach the ground) of `(x_(2) - x_(1))` = the relative position of second stone with respect to first with time (t) `(v_(2) - v_(1))` = the relative velocity of second stone with respect to first with time (t). Assuming that stones do not rebound after hitting.A. B. C. D. |
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Answer» Correct Answer - A::D While both the stones are in flight `a_(1) =g` and `a_(2) =g` So `a_("rel") = 0 rArr V_("rel")` = constant `rArr x_("rel") =` (const) t `rArr` Curve of `x_("rel") v//s t` will be straight line. `X_("rel")` will be straight line. After the first particle drops on ground, the seperation `(x_("rel"))` will decrease parabolically (due to gravitational acceleration) and finally becomes zero. and `V_("rel")` = slope of `x_("rel") v//s t` `x_("rel") t` |
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