Two springs A and B(kA = 2kB) are stretched by applying forces of equa

1.	Two springs A and B(kA = 2kB) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, that in B is (a) E/2 (b) 2E (c) E (d) E/4.
Answer» (b) 2E. Explanation:- Since (k_A = 2k_B) it means for the same force x_B = 2x_A . So if energy stored in spring A = E = F.x_A Energy stored in spring B = F.x_B =F.2x_A =2E

Two springs A and B(kA = 2kB) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, that in B is (a) E/2 (b) 2E (c) E (d) E/4.

Answer»

(b) 2E.

Explanation:-

Since (k_A = 2k_B) it means for the same force x_B = 2x_A . So if energy stored in spring A = E = F.x_A Energy stored in spring B = F.x_B =F.2x_A =2E